An inductor stores u energy and I current is passed through it and dissipate energy at the rate of P.The time constant of the circuit,when this coil is connected across a battery of zero internal resistance?

Answer is 2U/p

1 Answer
Apr 25, 2018

Energy stored in an inductor #L# is given by

#U=1/2LI^2#
where #I# is final value of the current.

Power dissipated #P# in a resistor #R# is given as

#P=I^2R#

Time constant of #LR# circuit is given as

#tau = L/R#

Writing it in terms of #Land R#, and noting that internal resistance of the battery is zero, we get

#tau=((2U)/I^2)/(P/I^2)#
#tau=(2U)/(P)#