An isosceles triangle has sides A, B, and C, such that sides A and B have the same length. Side C has a length of 4 and the triangle has an area of 128. What are the lengths of sides A and B?

1 Answer
Nov 11, 2017

A=B=1041

Explanation:

When in doubt, draw a diagram.

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h is the perpendicular bisector of AB from C, and meets AB at point D.

Sidenote: I have labeled this diagram according to the convention, with angles A,B and C opposite sides a,b and c respectively. So where you have A and B, I have a and b. Just a note.

We know that Area=12×base×height. In here, the base is length 4, and the height is h.

128=12×4h
128=2h
h=64

Now, focus just on BCD (or ACD). To work out the remaining length a (and b=a since the is isosceles) we need to use the Pythagorean Theorem. We have a base of 2, since it is half of the length 4 (remember that h is a bisector).

22+642=a2
a2=4100
a=4100=1041

Convert back to the format given in the question:

A=B=1041