An object is at rest at (4 ,5 ,1 ) and constantly accelerates at a rate of 5/3 m/s^2 as it moves to point B. If point B is at (7 ,5 ,3 ), how long will it take for the object to reach point B? Assume that all coordinates are in meters.

Nov 17, 2016

$t = 2.08$ s

Explanation:

${s}^{2} = {\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({z}_{2} - {z}_{1}\right)}^{2}$
${s}^{2} = 13$
$s = \sqrt{13}$

An object is at rest ${v}_{0} = 0$
$s = {v}_{o} t + a {t}^{2} / 2 = a {t}^{2} / 2$
$t = \sqrt{2 \frac{s}{a}}$
t=sqrt(2*sqrt(13)/5*3
$t = 2.08$ s