An object is at rest at #(7 ,6 ,4 )# and constantly accelerates at a rate of #7/4 m/s^2# as it moves to point B. If point B is at #(5 ,5 ,7 )#, how long will it take for the object to reach point B? Assume that all coordinates are in meters.
t = 2.138 seconds
The distance formula is the square root of the sum of the squares of the changes in x, y, z.
that vector is < 7-5 , 6-5 , 4-7 > = < 2 , 1 , -3 >
The sum of squares is 4 + 1 + 9 = 14
So the distance is
s = v t ==> t = s / v =