# An object is at rest at (7 ,9 ,4 ) and constantly accelerates at a rate of 7/4 m/s^2 as it moves to point B. If point B is at (7 ,1 ,6 ), how long will it take for the object to reach point B? Assume that all coordinates are in meters.

Mar 4, 2018

$3.071 s$

#### Explanation:

In this pathway,net displacement of the object is $\sqrt{{\left(7 - 1\right)}^{2} + {\left(1 - 9\right)}^{2} + {\left(6 - 4\right)}^{2}} = 8.25 m$

So,to calculate time required for this motion under constant acceleration $a$ we can use,

$s = u t + \frac{1}{2} a {t}^{2}$

Here, $u = 0$ (as the object was initially at rest)

and, $a = \frac{7}{4} , s = 8.25$

So, $t = 3.071 s$