An object is at rest at (9,1,3) and constantly accelerates at a rate of 14ms2 as it moves to point B. If point B is at (6,8,2), how long will it take for the object to reach point B? Assume that all coordinates are in meters.

1 Answer
Aug 11, 2017

The time is =15.7s

Explanation:

The distance AB is

AB=(69)2+(81)2+(23)2=(3)2+(7)2+(1)2

=9+49+1=59m

The acceleration is a=14ms2

The initial velocity is u=0ms1

We apply the equation of motion

s=ut+12at2

So,

59=0+12(14)2t2

t2=3259

t=3259=15.7s