# An object of mass m is circulating in a circular path of radius r with help of the centripetal force -k/r^2. Total kinetic energy of the object is???(rotation of rigid body)

Aug 27, 2017

See below.

#### Explanation:

The object is rotating in a circular path then

$- \frac{k}{r} ^ 2 + m {\omega}^{2} r = 0$

The kinetic energy is given by

$E = \frac{1}{2} J {\omega}^{2} = \frac{1}{2} m {r}^{2} \frac{k}{m {r}^{3}} = \frac{1}{2} \frac{k}{r}$

and

$\omega = \sqrt{\frac{k}{m {r}^{3}}}$