# An object's two dimensional velocity is given by #v(t) = ( sqrt(t-2)-2t , t^2)#. What is the object's rate and direction of acceleration at #t=3 #?

##### 2 Answers

Mar 29, 2017

#### Answer:

2nd quandrant (negative x and positive y)

#### Explanation:

When you put 3 (for t), you will get v(t) = (-5, 9). The distance (if speed is expressed as m/s and time is expressed as s) 30.89 meters.

Note that the units of time and velocity were not provided in the original question.

Mar 29, 2017

#### Answer:

The rate of acceleration is

#### Explanation:

The acceleration is the derivative of the velocity

Therefore,

The rate of acceleration is

The angle is in the 2nd quadrant and is