An object's two dimensional velocity is given by #v(t) = ( t^2, t-t^2sin(pi/3)t)#. What is the object's rate and direction of acceleration at #t=4 #?
1 Answer
Dec 26, 2016
Please see the explanation.
Explanation:
The magnitude of the acceleration is
I used WolframAlpha to evaluate the above at t = 4:
The direction is along the unit vector: