# An object was measured by a worker as 17.4 cm long; however, the manufacturer specifications list the length of the object at 17.9 cm. What is the percent error in the workers measurement?

Oct 23, 2017

2.79% error

#### Explanation:

Percent error $= 100 \times \frac{A c t u a l - M e a s u red}{A c t u a l}$

You can compute percent error now:

Percent error $= 100 \times \frac{17.9 - 17.4}{17.9}$

Percent error $= 100 \times \frac{0.5}{17.9} = \frac{50}{17.9} = 2.79$

Percent error is 2.79.