An object was measured by a worker as 17.4 cm long; however, the manufacturer specifications list the length of the object at 17.9 cm. What is the percent error in the workers measurement?

1 Answer
G_Ozdilek
Oct 23, 2017

2.79% error

Explanation:

Percent error #= 100times(Actual-Measured)/(Actual)#

You can compute percent error now:

Percent error #= 100times(17.9-17.4)/17.9#

Percent error #= 100times0.5/17.9 = 50/17.9 = 2.79#

Percent error is 2.79.

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