# An object with a mass of 32 g is dropped into 480 mL of water at 0^@C. If the object cools by 120 ^@C and the water warms by 9 ^@C, what is the specific heat of the material that the object is made of?

Feb 17, 2016

${c}_{o} = 1 , 125 \text{ may be ammonia liquid}$

#### Explanation:

${Q}_{o} = {m}_{o} \cdot {c}_{o} \cdot \Delta {t}_{o} \text{ Heat given by object a mass of 32 g}$
${c}_{o} \text{: specific heat of object}$
${Q}_{o} = 32 \cdot {c}_{o} \cdot 120$
${Q}_{o} = 3840 \cdot {c}_{o}$
${Q}_{w} = {m}_{w} \cdot {c}_{w} \cdot \Delta {t}_{w} \text{ Heat gained by water}$
V_=480 m ; m_=480 g ; c_w=1
${Q}_{w} = 480 \cdot 1 \cdot 9$
${Q}_{w} = 4320 C a l$
${Q}_{o} = {Q}_{w} \text{ conversation of energy}$
$3840 \cdot {c}_{o} = 4320$
${c}_{o} = \frac{4320}{3840}$
${c}_{o} = 1 , 125 \text{ may be ammonia liquid}$