An object with a mass of #4 kg#, temperature of #240 ^oC#, and a specific heat of #25 J/(kg*K)# is dropped into a container with #36 L # of water at #0^oC #. Does the water evaporate? If not, by how much does the water's temperature change?
1 Answer
Jun 19, 2017
water's temperature change = 0,16°C
Explanation:
The object decrease its temperature toward a final temperature Tf giving an amount of heat that is:
The water increases its temperature acquiring an egual amount of heat:
Equalizing the two quantities of heat you have:
Simplifying
and resolving
480 - 2Tf = 3000 Tf
3002 Tf = 480
Tf = 0,16 °C
note that: 36 L of water are 36 kg; specific heat of water is (4186 J)/kg K); the specific heat of the object is really very small