# An object with a mass of #4 kg#, temperature of #240 ^oC#, and a specific heat of #25 J/(kg*K)# is dropped into a container with #36 L # of water at #0^oC #. Does the water evaporate? If not, by how much does the water's temperature change?

##### 1 Answer

Jun 19, 2017

#### Answer:

water's temperature change = 0,16°C

#### Explanation:

The object decrease its temperature toward a final temperature Tf giving an amount of heat that is:

The water increases its temperature acquiring an egual amount of heat:

Equalizing the two quantities of heat you have:

Simplifying

and resolving

480 - 2Tf = 3000 Tf

3002 Tf = 480

Tf = 0,16 °C

note that: 36 L of water are 36 kg; specific heat of water is (4186 J)/kg K); the specific heat of the object is really very small