# An object with a mass of 50 g is dropped into 300 mL of water at 0^@C. If the object cools by 80 ^@C and the water warms by 5 ^@C, what is the specific heat of the material that the object is made of?

Jun 25, 2016

#### Answer:

Specific heat of the material that the object is made of is $0.375$.

#### Explanation:

Let the specific heat of the object of mass $50 g$ be $s$. As the object cools by ${80}^{o} C$, heat lost by it s

$50 \times 80 \times s = 4000 s$

Heat gained by water (assuming container has not gained any heat) is $300 \times 5 \times 1 = 1500$ - as each $m L$ of water is $1 g$.

Hence $4000 s = 1500$ and $s = \frac{1500}{4000} = 0.375$