# An object with a mass of 7 kg is hanging from a spring with a constant of 3 (kg)/s^2. If the spring is stretched by  2 m, what is the net force on the object?

Jan 21, 2017

The net force $= 62.6 N$

#### Explanation:

We use Hooke's law

$F = k x$

$x = 2 m$

$k = 3 k g {s}^{-} 2$

$F = 3 \cdot 2 = 6 N$

The net force $= 7 g - 6 = 62.6 N$