An oxygen gas container has a volume of 20.0 L. How many grams of oxygen are in the container if the gas has a pressure of 876 mmHg at 23 C?
Use the ideal gas law. We are given the pressure, the temperature and the volume. The gas constant will be
We're looking for
#(20.0 L)(876 mmHg) = n(62.36 mmHg L k^-1 mol^-1)296K#
If we cancel all units we're left with
#n = 0.949 #mol
#"molar mass" = ("number of grams per sample")/("number of moles")#
And that the molar mass of oxygen is
#32.00 g/(mol) * 0.949 mol = g#
#g = 30.4 " grams"#
Notice I rounded to
Hopefully this helps!