Answer is 4 which order to solve? #3^0 (5^0 - 6^-1 * 3)/ 2^-1# I don't know if I should bring the #6^-1# down first or multiply by 3 first.
Following the order of operations, with the parentheses made explicit:
First, perform any operations within parentheses.
Within those parentheses, we treat numerators and denominators as having parentheses around them, and so perform operations within those first.
Evaluate any exponents. Recall that if
Perform any multiplication or division, going left to right.
Perform any addition or subtraction, going left to right.
All operations in the numerator have been completed. Moving to the denominator, we have an exponent to evaluate.
We now perform the remaining division. Recall that any nonzero number divided by itself is
All operations within parentheses have been evaluated. Going back, we now evaluate the remaining exponents.
And finally, we perform the remaining multiplication.