How do you simplify #4times3^2+3times4^2+2(3times4)^2#?

3 Answers
Aug 6, 2016

Answer:

#4xx3^2+3xx4^2+2(3xx4)^2=372#

Explanation:

The order of operations is given by PEMDAS, which means parentheses, exponents, multiplication and division and addition and subtraction in that order.

Hence, #4xx3^2+3xx4^2+2(3xx4)^2#

= #4xx3^2+3xx4^2+2xx12^2#

= #4xx9+3xx16+2xx144#

= #36+48+288#

= #372#

Aug 6, 2016

Answer:

#372#

Explanation:

Blindly following PEDMAS/BODMAS/PEMDAS or any other version, without understanding what it actually means, will often lead to incorrect answers.

Strongest operations (powers and roots) are done first, then multiplication and division, and lastly the weakest operations of addition and subtraction.

However, sometimes a weaker operation must be done first and in this case parentheses are used.

Count the number of terms first. You can perform operations in any term independent of other terms. Each term must simplify to a single value. The final values are added and subtracted in the LAST step.

#color(red)(4xx3^2)color(blue)(+3xx4^2)color(green)(+2(3xx4)^2)" has 3 terms"#

=#color(red)(4xx9)color(blue)(+3xx16)color(green)(+2(12)^2)#

=#color(red)(36)color(blue)(+48)color(green)(+2(144)#

=#color(red)(36)color(blue)(+48)color(green)(+288)#

=#372#

Jan 18, 2017

Answer:

372

Explanation:

PEMDAS

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

#4*3^2+3*4^2+2(3*4)^2#
#4*3^2+3*4^2+2*12^2#
#4*9+3*16+2*144#
#36+48+288#
#376#