Arsenic reacts with chlorine to form a chloride. If 1.587 g of arsenic reacts with 3.755 g of chlorine what is the empirical formula of the chloride?

1 Answer
Jul 10, 2016

Answer:

#AsCl_5#

Explanation:

#"Moles of arsenic"# #=# #(1.587*g)/(74.92*g*mol^-1)=0.0212*mol#.

#"Moles of chlorine"# #=# #(3.755*g)/(35.45*g*mol^-1)=0.106*mol#.

We divide thru by the lowest molar quantity to give #AsCl_5#. This is not chemical you would find in a bottle on a shelf.