# Arsenic reacts with chlorine to form a chloride. If 1.587 g of arsenic reacts with 3.755 g of chlorine what is the empirical formula of the chloride?

$A s C {l}_{5}$
$\text{Moles of arsenic}$ $=$ $\frac{1.587 \cdot g}{74.92 \cdot g \cdot m o {l}^{-} 1} = 0.0212 \cdot m o l$.
$\text{Moles of chlorine}$ $=$ $\frac{3.755 \cdot g}{35.45 \cdot g \cdot m o {l}^{-} 1} = 0.106 \cdot m o l$.
We divide thru by the lowest molar quantity to give $A s C {l}_{5}$. This is not chemical you would find in a bottle on a shelf.