Assuming human skin is at 98.6 degrees Fahrenheit, what wavelength is the peak in the human thermal radiation spectrum? What type of waves are these?

2 Answers
Mar 13, 2016

#lambda_(max)=9.34 mu m# which is called infrared light.

Explanation:

Wien's displacement law states that the black-body radiation curve for different temperatures peaks at a wavelength inversely proportional to the temperature.

#lambda_(max)=b/T#

where b is Wien's displacement constant, equal to #2.898×10^(−3) m K# and #T# is the temperature in Kelvin. The temperature we were given needs to be converted to Kelvin:

#T = (T_F-32^oF)*(5K)/(1^oF) + 273K = 310.15K#

plugging this into our equation, we get the peak wavelength of radiated light:

#lambda_(max)=(2.898×10^(−3) m K)/(310.15K)=9.34x10^-6m=9.34 mu m#

This is in the range of what is called infrared radiation.

Mar 13, 2016

Should be the infrared fingerprint region.


We have a relationship for this called Wien's Displacement Law:

#\mathbf(lambda_max = b/T)#

where:

  • #b = 2.89777xx10^(-3)# #"m"cdot"K"# is a proportionality constant, probably experimentally determined.
  • #T# is temperature in #"K"#.
  • #lambda_max# is the wavelength that you observe at its largest spectral energy density.

The spectral energy density is depicted in the following diagram, with respect to wavelength in #"nm"#:

https://upload.wikimedia.org/

You can think of the spectral energy density as being proportional to the contribution of each wavelength range to some final observed color at a particular temperature. You can see that the peaks would correspond to #lambda_max#.

Converting temperature to #"K"#, we get:

#(98.6^@ "F" - 32) xx 5/9 = 37^@ "C"#

#37 + 273.15 ~~ color(green)("310.15 K")#

And now we get a max wavelength of:

#lambda_max = (2.89777xx10^(-3) "m"cdotcancel"K")/("310.15" cancel"K")#

#= 9.343xx10^(-6) "m"#

Converting this to #mu"m"#, we get:

#= 9.343xx10^(-6) cancel("m") xx (10^6 mu"m")/(1 cancel"m")#

#= color(blue)(9.343)# #color(blue)(mu"m")#

http://thesuiteworld.com/

Being close to #10# #mu"m"#, I find that it's close to the infrared region. And if you convert to #"cm"^(-1)#, you should get #"1070.32 cm"^(-1)#, which is within the "fingerprint" region of the IR spectrum.