At a constant temperature, a gas that exerted a pressure of 2.43 atm and that occupied 1.87 L is compressed until its pressure is 6.35 atm. What is the final volume?

1 Answer
Rita
May 13, 2018

#0.72L# = #V_2#

Explanation:

We start with Boyle's law
#(P_1)(V_1)# = #(P_2)(V_2)#

  • We know its this equation due to the fact that the temperature is constant

We don't need to do any conversions, so we can plug our values in

#P_1# = #2.43atm#
#V_1# = #1.87L#
#P_2# = #6.25atm#
#V_2# = unknown (what we're solving for)

#(2.43atm)(1.87L)# = #(6.35atm)(V_2)#

  • Divide the #6.35atm# on both sides, this will also cancel out the #atm# units, leaving us with #L#

#((2.43cancel(atm))(1.87L))/(6.35cancel(atm))# = #((cancel(6.35atm))(V_2))/(cancel(6.35atm))#

  • now multiply #2.43# by #1.87L# and divide by #6.35#

#0.72L# = #V_2#

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