# At STP, what is the volume of 7.08 mol of nitrogen gas?

$158.592 {\mathrm{dm}}^{3}$
At STP the molar volume of all gases is $22.4 {\mathrm{dm}}^{3} / m o l .$
So hence $7.08 m o l$ of any gas at STP would occupy a volume of $7.08 \times 22.4 = 158.592 {\mathrm{dm}}^{3}$.