# Calcium oxide and carbon dioxide are produced from the decomposition of calcium carbonate. How many moles of calcium carbonate are needed to produce 15.0 grams of the calcium oxide?

Jun 30, 2017

Approx. $0.27 \cdot m o l$.........

#### Explanation:

We interrogate the stoichiometric equation......

$C a C {O}_{3} \left(s\right) + \Delta \rightarrow C a O \left(s\right) + C {O}_{2} \left(g\right) \uparrow$

We require a molar quantity of $\frac{15.0 \cdot g}{56.08 \cdot g \cdot m o {l}^{-} 1} = 0.268 \cdot m o l ,$ with respect to $\text{calcium oxide}$.

And clearly, we need a molar quantity of AT LEAST $0.268 \cdot m o l$ $C a C {O}_{3}$, i.e. a quantity consistent with 1:1 molar relationship given by the stoichiometric equation.

What mass of $\text{calcium carbonate}$ does this represent?