Calculate the gradient of the curve at the point where x = 1 ? y = x^3 +7

2 Answers
Jun 17, 2018

Gradient is #3#.

Explanation:

Gradient of a curve #y=x^3+7# is given by its derivative #(dy)/(dx)#.

As #y=x^3+7#, #(dy)/(dx)=3x^2#

And therefore gradient at #x=1# is #(dy)/(dx)=3*1^2=3*1=3#

Jun 17, 2018

Slope of the curve at #(x=1)=3#

Explanation:

Given -

#y=x^3+7#

Slope of the curve is given by the first derivative.

#dy/dx=3x^2#

At #x=1# The slope of the curve -

At #x=1; dy/dx=3(1^2)= 3#

Slope of the curve at #(x=1)=3#