# Calculate the volume of ammonia gas produced at STP when 140g of nitrogen gas reacts with 30g of hydrogen gas.(atomic mass: N=14u,H=1u) how to do this?

Aug 18, 2017

Ans:color(red)((10×22.4L=224"L")

#### Explanation:

Simply, the reaction is ${N}_{2} + 3 {H}_{2} = 2 N {H}_{3}$
$140 g$ ${\text{N}}_{2}$ means $\frac{140}{28} = 5$ mol;
$30 g$ ${H}_{2}$ means $\frac{30}{2} = 15$mol
From 1 mol of ${N}_{2}$ 2 mol $N {H}_{3}$ is prepared in perfect presence of ${H}_{2}$
Hence, $10$mol of $N {H}_{3}$ will be produced.
We know,1mol of any ideal gas at STP (${0}^{\circ} \text{C}$ and $\text{1 atm}$) contains 22.4L of the ideal gas.

Produced ammonia is $224 \text{ L}$.