Question

Can anybody help me? (3^-2 * b^2) / (a^0 * b^2)

(3^-2 * b^2) / (a^0 * b^2)

Answer 1

`rarr(3^(-2)*b^2)/(a^0*b^2`

`=(cancel(b^2))/(3^2*1*cancel(b^2))=1/9`