Can someone check my homework?

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Answer 1 · 2018-05-18T08:36:26

See below.

Part i)

If we are to assume that the triangle #OSF# is right angled at #ShatOF# the the distance #SF# is found by Pythagoras' theorem:

#SF=sqrt(10^2+12^2)=sqrt(244)=2sqrt(61)#

Rowing at #8kmh^(-1)#

#"time"="distance"/"speed"=(2sqrt(61))/8=1.96color(white)(8)#hrs

nearest hundredth

I don't know where you got the u from in your calculation, unless I'm missing something here.

Part ii)

This is really the same thing:

To row from S to O

#10/8#hr

To run from O to F:

#12/14#hr

Total time:

#10/8+12/14=59/28=2.11color(white)(8)#hrs

nearest hundredth