# Can someone explain how to do this? Consider the following equation: 2ZnS(s) + 3O2(g) ---> 2ZnO(s) + 2SO2(g), ΔH° = –878.2 kJ. How much heat is released when 3.0 mol ZnS(s) reacts in excess oxygen?

Jul 1, 2014

In this question a chemical equation is given;

2ZnS + 3${O}_{2}$ -----------> 2 ZnO + 2S${O}_{2}$ Enthalpy Change = -872 kJ

as per the equation 2 moles of ZnS produces -872.8kJ of energy on reaction with Oxygen.

2 moles of ZnS = -872 kJ of heat energy

1 mole of ZnS gives -872kJ/2 = -436 kJ of heat Energy

3 moles of ZnS will produce = -436 kJ x 3 = -1308 kJ of energy.