Question

Can someone help me solve this problem with law of sines?

Answer 1

Answer is `5.9`

Explanation:

As `m/_A=15^@` and `m/_B=20^@`, `m/_C=180^@-15^@-29^@-145^@`

Now according to sine law,

`a/sinA=b/sinB=c/sinC`, here `a=BC`, `b=AC` and `c=AB`

Hence `a/(sin15^@)=b/(sin20^@)=10/(sin145^@)`

and `AC=b=10/(sin145^@)xxsin20^@`

= `10/0.5736xx0.3420=5.962~=5.9`

Hence answer is `5.9`