Can someone help me solve this trigonometric equation problem step by step? Thank You!

Solve the equation within [0,2π][0,2π]. Write your solutions separated with commas. If no solutions exist, write no solution.

6sin(x−2)=14

1 Answer
Jun 3, 2018

This question 6sin(x-2) = 14 is wrong. Hence No Solution

Explanation:

Since, The value of sinx can only lie between [1,-1] for any value of x in RR.
i.e -1<=sinx<=1 for every x in RR

so in the equation

6sin(x-2) = 14

rArr sin(x-2) = 2.33

and 2.33>1

Therefore the question is wrong since the value of the sin can never be 2.33.