Can you combine #y^ { 2} \sqrt { 3y ^ { 2} } - 4v \sqrt { 48y ^ { 5} }#? If so, how?

1 Answer
Apr 11, 2017

No, you can't combine. You can simplify, though.

Explanation:

First, we observe that #48 = 16 * 3#. Hence, the radical becomes

#y^2sqrt(3y^2) - 4vsqrt(16 * 3 * y^5)#

#y^2sqrt(3y^2) - 4v(4)sqrt(3y^5)#

#y^2sqrt(3y^2) - 16vsqrt(3y^5)#

Now consider the variables. We have that #sqrt(y^2) = (y^2)^(1/2) = y#. Hence,

#y^2(y)sqrt(3) - 16vsqrt(3(y^2)^2y)#

#y^3sqrt(3) - 16vy^2sqrt(3y)#

Since #sqrt(3)# and #sqrt(3y)# aren't like terms, we cannot combine them, and this is as far as we can go.

Hopefully this helps!