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Answer 1 · 2018-03-12T08:48:43

(C) $27.5 %$ $27.5%$ acid

Explanation:

In $1$ $1$ liter of $40 %$ $40%$ acid we have $\frac{40}{100}$ $40/100$ liter of acid, so in $15$ $15$ liter of $40 %$ $40%$ acid, we will have

$\frac{40}{100} \times 15 = \frac{600}{100} = 6$ $40/100xx15=600/100=6$ liters of acid.

Similarly, in $1$ $1$ liter of $20 %$ $20%$ acid we have $\frac{20}{100}$ $20/100$ liter of acid, so in $25$ $25$ liter of $20 %$ $20%$ acid, we will have

$\frac{20}{100} \times 25 = \frac{500}{100} = 5$ $20/100xx25=500/100=5$ liters of acid.

Therefore in $15 + 25 = 40$ $15+25=40$ liters of mix, we have $6 + 5 = 11$ $6+5=11$ liters of acid

and in $1$ $1$ liter, we have $\frac{11}{40}$ $11/40$ liters of acid i.e.

$\frac{11}{40} \times 100 = 11 \times 2.5 = 27.5 %$ $11/40xx100=11xx2.5=27.5%$ acid and answer is $(C)$ $(C)$

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