Can you please help answer this? Solid lead (II) iodide forms when aqueous solutions of potassium iodide and lead (II) nitrate are mixed. Write the molecular equation and include state symbols.

Please explain how you got the answer.

1 Answer
Feb 17, 2018

Pb(NO_3)_2 + 2KI\rightarrow PbI_2 + 2 KNO_3

Explanation:

Lead (II) iodide or lead iodide is a salt with the formula PbI_2. At room temperature, it is a bright yellow odorless crystalline solid, that becomes orange and red when heated. It was formerly called plumbous iodide.

Preparation:

PbI_2 is commonly synthesized via a double displacement reaction between potassium iodide KI and lead(II) nitrate Pb(NO_3)_2 in water solution:

Pb(NO_3)_2 + 2KI\rightarrow PbI_2 + 2 KNO_3

While the potassium nitrate KNO_3 is soluble, the lead iodide PbI_2 is nearly insoluble at room temperature, and thus precipitates out.


**Read more about it, **"https://en.wikipedia.org/wiki/Lead(II)_iodide"