# Convert heat of combustion of kerosene jet fuel to kJ/mol kerosene?

## The heat of combustion of jet fuel is 44.7 MJ/kg. A Boeing 747 burns 1.50 x 10^5 liters of jet fuel over the course of a 10 hour flight.If the density of jet fuel is 0.790 g/mL,how much heat would be released by the combustion of jet fuel during a 10 hrs?

Apr 23, 2018

To answer the question, you don't need to jump to kJ/mole. You can, but you've got to look up the molar mass - it is an unnecessary step. See below.

#### Explanation:

Living in Beijing, I fly 10 hours to California 4 times a year - my carbon footprint isn't getting smaller. Ugh.

Anyway, in those 10 hours, the plane burns $1.50 \times {10}^{5}$L
Based on the density, that means it is burning:
$\left(0.790 \frac{\text{kg}}{L}\right) \times 1.50 \times {10}^{5} L$ = 118,500 kg Kerosene

And this fuels kicks out 44.7 million Joules per kilogram.
$44.7 \times {10}^{6} \frac{J}{\text{kg}} \times 118 , 500 k g = 5.3 \times {10}^{12} J$

5.3 trillion joules.