# Could i have some help please ??

## May 22, 2018

Well, we can tell you the molar quantity associated with $1 \cdot g$ of sucrose...

#### Explanation:

$\text{Number of moles"="mass of stuff"/"molar mass of substance}$

$\frac{1.00 \cdot g}{{\underbrace{342.30 \cdot g \cdot m o {l}^{-} 1}}_{\text{molar mass of sucrose}}} = 2.92 \times {10}^{-} 3 \cdot m o l$

May 22, 2018

0.002 92 mol sucrose; 0.003 90 mol palmitic acid

#### Explanation:

Moles of sucrose

The formula of sucrose is ${\text{C"_12"H"_22"O}}_{11}$.

"M_text(r) = 342.30

$\text{Moles of sucrose" = 1.00 color(red)(cancel(color(black)("g sucrose"))) × "1 mol sucrose"/(342.30 color(red)(cancel(color(black)("g sucrose")))) = "0.002 92 mol sucrose}$

Moles of palmitic acid

The formula of palmitic acid is ${\text{C"_16"H"_32"O}}_{2}$.

"M_text(r) = 256.42

$\text{Moles of palmitic acid" = 1.00 color(red)(cancel(color(black)("g palmitic acid"))) × "1 mol palmitic acid"/(256.42 color(red)(cancel(color(black)("g palmitic acid")))) = "0.003 90 mol palmitic acid}$