# Determine the molarity of a solution formed by dissolving 648 mg of MgCl2 in enough water to yield 150.0 mL of solution?

Approx. $0.05 \cdot m o l \cdot {L}^{-} 1$ with respect to $\text{magnesium chloride.}$
$\text{Molarity"="Moles of solute"/"Vollume of solution}$
=((648xx10^-3*g)/(95.21*g*mol^-1))/(150.0xx10^-3*L)=??*mol*L^-1.
What is the concentration with respect to $C {l}^{-}$?