Diamonds have a density of 3.52 g/mL. What is the volume (in units of cm3) of a diamond with a mass of 21 g?

2 Answers
Dec 20, 2017

Approx. 6*cm^36cm3...that's a big sparkler....and I think this is the famous "Kohi-noor"Kohi-noor, the one that presently lies in QE11's crown.....

Explanation:

By definition rho_"density"="mass"/"volume"ρdensity=massvolume

And thus if we want volume we take the quotient....

"volume"="mass"/rho=(21*g)/(3.52*g*mL^-1)=??*mLvolume=massρ=21g3.52gmL1=??mL...is this quotient dimensionally consistent? Why?

Dec 20, 2017

5.97 cm^35.97cm3

Explanation:

Using the equation:
Density (gcm^(-3)) = (Mass (g)) / (Volume (cm^3)Density(gcm3)=Mass(g)Volume(cm3)

Rearrange for volume:
Volume (cm^3) = (Mass (g)) / (Density (gcm^(-3)))Volume(cm3)=Mass(g)Density(gcm3)

Volume = (21 g) / (3.52 gcm^(-3))Volume=21g3.52gcm3

Volume = 5.97 cm^3Volume=5.97cm3

A note on units
cm^3cm3 is another way of writing mLmL
gcm^(-3)gcm3 is another way of writing gg/cm^3cm3