Question

Differentiate y=ln(3x^2e^tanx)?

Answer 1

`(dy)/(dx)=2/x+sec^2x`

Explanation:

First we just simplify it.

`y=ln(3x^2e^tanx)`

= `ln(3x^2)+ln(e^tanx)`

= `ln3+2lnx+tanx`

and now differentiating

`(dy)/(dx)=2/x+sec^2x`