# Evaluate #lim_(x->0)(1-cosx)/x^2#?

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Thanks!

Thanks!

##### 3 Answers

#### Explanation:

L'Hopital's rules says that the

Using this, we get

Yet as the denominator is

So, in total

#### Explanation:

# = (1-cos^2x)/(x^2(1+cosx)#

# = sin^2x/(x^2(1+cosx)#

#= sin^2x/x^2 * 1/(1+cosx)#

#### Explanation:

We see that through direct evaluation, we get indeterminate form,

We can take the derivative of our numerator and denominator function to obtain the new limit

Through direct evaluation, we would get indeterminate form again, so we can take the derivatives once more to get

When we evaluate this limit at zero, we get

Hope this helps!