# Find dy/dx (Implicit differentiation)?

## I don't think I'm doing this right... If anybody could solve it. ${x}^{2} + x y - \sqrt{y} = 3$ Thank you!

$2 x + y + x \frac{\mathrm{dy}}{\mathrm{dx}} - \frac{1}{2} \cdot {y}^{- \frac{1}{2}} \cdot \frac{\mathrm{dy}}{\mathrm{dx}} = 0$
$2 x + y + \left(x - \frac{1}{2 \sqrt{y}}\right) \frac{\mathrm{dy}}{\mathrm{dx}} = 0$
$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{2 x + y}{\frac{1}{2 \sqrt{y}} - x}$