Find entropy, enthalpy, Gibbs free energy of reaction at 298K. Find if it is exothermic and whether it is spontaneous? C3H8 + 502 -> 3CO2 + 4H2O
Hf (kJ/mol)
C3H8 = -103.85
O2 = 0
C02 = -393.5
H20 = -286
S (J/Mol K)
C3H8 = 269.9
O2 = 205
C02 = 214
H20 = 70
Hf (kJ/mol)
C3H8 = -103.85
O2 = 0
C02 = -393.5
H20 = -286
S (J/Mol K)
C3H8 = 269.9
O2 = 205
C02 = 214
H20 = 70
1 Answer
Here's what I get.
Explanation:
You have the following information.
Calculate the enthalpy of reaction
The formula for enthalpy of reaction is
#color(blue)(|bar(ul(color(white)(a/a) Δ_rH = sumΔ_fH_text(products) - sumΔ_fH_text(reactants)color(white)(a/a)|)))" "#
∴
Calculate the entropy of reaction
The formula for the entropy of reaction is
#color(blue)(|bar(ul(color(white)(a/a)Δ_rS = sumS_text(products) - sumS_text(reactants)color(white)(a/a)|)))" "#
∴
Calculate the Gibbs free energy change for the reaction
The formula for free energy change is
#color(blue)(|bar(ul(color(white)(a/a)ΔG = ΔH - TΔScolor(white)(a/a)|)))" "#
∴
Summary