# Find entropy, enthalpy, Gibbs free energy of reaction at 298K. Find if it is exothermic and whether it is spontaneous? C3H8 + 502 -> 3CO2 + 4H2O

##
Hf (kJ/mol)

C3H8 = -103.85

O2 = 0

C02 = -393.5

H20 = -286

S (J/Mol K)

C3H8 = 269.9

O2 = 205

C02 = 214

H20 = 70

Hf (kJ/mol)

C3H8 = -103.85

O2 = 0

C02 = -393.5

H20 = -286

S (J/Mol K)

C3H8 = 269.9

O2 = 205

C02 = 214

H20 = 70

##### 1 Answer

#### Answer:

Here's what I get.

#### Explanation:

You have the following information.

**Calculate the enthalpy of reaction**

The formula for enthalpy of reaction is

#color(blue)(|bar(ul(color(white)(a/a) Δ_rH = sumΔ_fH_text(products) - sumΔ_fH_text(reactants)color(white)(a/a)|)))" "#

∴

**exothermic**.

**Calculate the entropy of reaction**

The formula for the entropy of reaction is

#color(blue)(|bar(ul(color(white)(a/a)Δ_rS = sumS_text(products) - sumS_text(reactants)color(white)(a/a)|)))" "#

∴

**Calculate the Gibbs free energy change for the reaction**

The formula for free energy change is

#color(blue)(|bar(ul(color(white)(a/a)ΔG = ΔH - TΔScolor(white)(a/a)|)))" "#

∴

**spontaneous**.

**Summary**

**exothermic**

**spontaneous**