Find the area of a regular octagon with an apothem of 8.5.?

1 Answer

#A = 238 " "units^2#

Explanation:

Area of a regular polygon #= 1/2 xx perimeter xx apothem#

#A = (Pa)/2#

Perimeter #= "number of sides" xx "side length"#

#P = ns = 8s#

#A = (8s*8.5)/2 = 34s#

Since we know that the octagon is regular and we know the apothem (height from a side to the center of the polygon, we can calculate the side length):

Each angle of the central angle: #(360^@)/8 = 45^@#

and each side of the polygon forms an isoceles triangle when joined to center. Further, a perpendicular from center to the side of the polygon divides the side in two equal parts and also cuts this angle at the center (#45^@#) in half i.e. #22.5^@#.

Using trigonometry, we can find half the side length (#x#):

#tan 22.5^@ = x/a = x/8.5#

#x = 8.5*tan 22.5^@ ~~ 3.52#

side length: #s = 2x ~~ 7#

#A = 34 * s ~~ 34 * 7 ~~238 " units"^2 #

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