# Find the cell potential of a galvanic cell zinc and copper ?

May 4, 2018

+1.101V

#### Explanation:

1. The 2 ionic half equations of the cell are given below.
Since zinc is more reactive than copper, zinc loses electrons more readily to form $Z {n}^{2 +}$ ions.
$Z n \left(s\right) \to Z {n}^{2 +} \left(a q\right) + 2 {e}^{-}$
$C {u}^{2 +} \left(a q\right) + 2 {e}^{-} \to C u \left(s\right)$
2. Look up the standard potentials for the half-reactions.
${E}^{o}$ for reduction of $c {u}^{2 +}$ is +0.339V
${E}^{o}$ for oxidation of $Z n$ is +0.762V

Cell potential
= +0.339V +0.762V
= +1.101V