# Find the differential of y in the function: y=x^3cosx ?

##### 1 Answer

Mar 4, 2018

#### Explanation:

We want to find the derivative of

#y=x^3cos(x)#

Use the product rule, if

then

#f=x^3=>f'=3x^2# #g=cos(x)=>g'=-sin(x)#

By the product rule

#dy/dx=3x^2cos(x)-x^3sin(x)#