Find the inflection point of the function #e^(-x/2)# ?
1 Answer
Sep 22, 2017
There are no inflection points.
Explanation:
The inflection point will be where the second derivative equals
Calling the function
#f(x) = e^(-x/2)#
#f'(x) = -1/2e^(-x/2)#
#f''(x) = 1/4e^(-x/2)#
If we set this to
#0 = 1/4e^(-x/2)#
Which doesn't have any solutions because
Hopefully this helps!