# Find the intersection point between #x^2+y^2-4x-2y=0# and the line #y=x-2# and then determine the tangent that those points?

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Find the intersection point between #x^2+y^2-4x-2y=0# and the line #y=x-2# and then determine the tangent that those points?

Find the intersection point between

##### 1 Answer

Intersection points are

#### Explanation:

For finding intersection point between

or

or

or

or

i.e.

and for

Hence intersection points are

As the slope of radius line joining

And as the slope of radius line joining

graph{(x^2+y^2-4x-2y)(x-y-2)(x+2y+1)(2x+y-10)=0 [-2.37, 7.63, -1.58, 3.42]}