# Find the largest integer such that 8 more than six times the integer is less than -42.?

Jul 1, 2017

The largest integer that satisfies this is $- 9$.

#### Explanation:

Translating this into an equation would be:

"Find the largest integer $x$ such that $6 x + 8 < - 42$."

Simplifying the inequality:

$6 x + 8 < - 42$

$6 x < - 50$

$x < - \setminus \frac{50}{6}$

$x < - 8.333$

So, the largest integer less than $- 8.333$ would be $- 9$.