For a school play, one adult ticket cost $5 and one student ticket cost $3. Twice as many student tickets as adult tickets were sold. The total receipts were $1650. How many of each kind of ticket were sold?

1 Answer

As the number of student tickets sold is twice the number of adult tickets, there is only one solution,
150 adult tickets and 300 student tickets.


The total was $1650
Let N be the number of adult tickets sold..
Then, the number of student tickets sold is 2N
So, N(5$) + 2N(3$ )= 1650$.
11N$ = 1650$.
N = 150.

Of course, (175, 275) is also a positive-integer solution that does not satisfy the given condition that the second number is twice the first.