For f(x) = .01(2)^xf(x)=.01(2)x, how do you find the average rate of change from x=12x=12 to x=15x=15?

1 Answer
Jan 27, 2017

81.92

Explanation:

Formula to remember :

The average rate of change

=( int f' dx)/(b-a), with x from a to b.

=[f]/(b-a), between x = a and b.

=(f(b)-f(a))/(b-a).

Here, it is

(-01 )(2^15 - 2^13)/(15-13)#

=81.92