Question

For `f(x)=x/(x+1)` and `g(x)=9/x`, how do you find `(fog)(x)`?

Answer 1

The answer is `=9/(9+x)`

Explanation:

This is a composition of functions

`f(x)=x/(x+1)`

`g(x)=9/x`

`(fog)(x)=f(g(x)`

`f(9/x)=(9/x)/((9/x)+1)=(9/x)/((9+x)/x)`

`=9/(9+x)`