For the experiment of tossing a coin three times, how do you find the probability of getting at least two heads?
Since we only have three throws it will be easier to list all possibilities, of 1st, 2nd and 3rd throws
Eight possibilities in all, and the requirement of at least two heads is shown in blue
total possible case :- HHH, HHT, HTH, THH, TTT, TTH, THT, HTT
At least two heads :- 4
so the probability of getting at least two head is 4/8 = 1/2